The first one is the only that might give you some trouble. The first thing you do is factor out the [tex] b^{2} [/tex]: [tex] b^{2} (2 x^{2} +5x+2)[/tex] and then you have to factor the rest using the quadratic formula. The whole thing factored looks like this, then: [tex] b^{2} (x+ \frac{1}{2})(x+2) [/tex] The second one can be factored straight out: (x-4)(x-4) Then the third one can be factored by taking roots. Recognize that [tex] x^{2} [/tex] is a perfect square and so is 49: [tex] x^{2} =49[/tex] and taking the square root of both sides gives you this: x = +/- 7
