Consider a triangle with vertices at S(-2,-3), A(2,3), and N(5,-4).

Part A: What is the shortest side of the triangle? Select the correct response.

A. Line SA
B. Line AN
C. Line NS
D. All sides are congruent.

Part B: Justify your answer from part A.

Respuesta :

the answer is A because the distance between it is shorter than the distance between+3 and -4



Answer:

Step-by-step explanation:

Given that a triangle has vertices S(-2,-3), A(2,3), and N(5,-4)

To find side lengths we can use distance formula between two vertices

SA =[tex]\sqrt{(2+2)^2+(3+3)^2} =\sqrt{52}[/tex]

AN=[tex]\sqrt{(5-2)^2+(-4-3)^2} \\=\sqrt{58}[/tex]

NS[tex]\sqrt{(5+2)^2+(-4+3)^2} \\=\sqrt{50}[/tex]

Thus comparing we find that side NS is the shortest side

Option C is right answer