09-09-2017
Physics

contestada

a cheetah can accelerate from rest at the rate of 4m /s

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jameskingfriend1 jameskingfriend1

09-09-2017

acceleration of cheetah (a) = 4m/s²
time = 10s
initial velocity(u) = 0
final velocity = v
distance travelled = s

v = u +at = 0 + 10×4 = 40m/s
s = (v²-u²)/2a = 40²/(2×4) = 1600/8 = 200m

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