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plz help. will give double points, comment, thanks and brainliest. plz

ABCD and EFG are parallel lines
BC = CF
Angle BFE =70°

work out the size of the angle marked x.
give reasons for each stage of your working.

(diagram not accurately drawn)

plz help will give double points comment thanks and brainliest plzABCD and EFG are parallel linesBC CFAngle BFE 70work out the size of the angle marked xgive re class=

Respuesta :

since ABCD and EFG are parallel, so the angle FBC = angle BFE = 70°
also note that the triangle is an isosceles triangle, so two of its angles will be equivalent
which in this case would be: Angle FBC = Angle CFB
so angle CFB = 70°
As the internal angles of a triangle should add up to 180°, so 70 + 70 + X = 180
X = 180-70-70 = 40°

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