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How much would $400 invested at 9% interest compounded continuously be worth after 3 years? Rounded by the nearest cent

Respuesta :

[tex]\bf \qquad \textit{Continuously Compounding Earned Amount} \\\\ A=Pe^{rt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$400\\ r=rate\to 9\%\to \frac{9}{100}\to &0.09\\ t=years\to &3 \end{cases} \\\\\\ A=400e^{0.09\cdot 3}[/tex]

notice, "e" is the Euler's constant, and yes, is on your calculator.

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