The mass of silver that can be prepared from 2.10 g of copper metal are 7.128 grams of Ag
calculation
Cu(s) + 2AgNO3 (aq) → Cu(NO3)2 +2 Ag (s)
find the moles of Cu
= mass/ molar mass
= 2.10 g / 63.5 g/mol = 0.033 moles
Use the mole ratio to determine the moles of Ag
The mole ratio of Cu : Ag is 1:2 therefore the moles of Ag = 0.033 x2=0.066 moles
mass of Ag = moles x molar mass
= 0.066 moles x 108 g/mol = 7.128 grams of Ag
