Respuesta :
what I can make out is, check the picture, that'd be the dimensions of the room.
therefore, the surface area of that room is
2 10x25 rectangles, front and back
2 30x10 rectangles, left and right
and 2 25x30 rectangles, top and bottom
so the area will be (2*10*25) + (2*30*10) + (2*25*30), which gives us 2600 square feet though, not yards.
let's add the doors, windows and others which is 1275, so 2600 + 1275, that gives us 3875 square feet.
now, the paint is 9.5 for square yard, no feet, so let's do some conversion then,
[tex]\bf \begin{array}{ll} yards&feet\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1yd&3ft\\ (1yd)^2&(3ft)^2\\ yd^2&3^2ft^2\\ &9ft^2 \end{array}[/tex]
so, if there are 9 square feet in one square yard, how many square yards are there in 3875 square feet?
[tex]\bf \begin{array}{ccll} yd^2&ft^2\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1&9\\ x&3875 \end{array}\implies \cfrac{1}{x}=\cfrac{9}{3875}\implies \cfrac{3875}{9}=x[/tex]
that's how many yd² are there in 3875 ft².
now, we know for every yd², is $9.50, so then the cost will be
[tex]\bf 9.5\cdot \cfrac{3875}{9}\implies \cfrac{95}{10}\cdot \cfrac{3875}{9}\implies \cfrac{73625}{18}~~\approx~~ \stackrel{\$}{4090.2778}[/tex]
therefore, the surface area of that room is
2 10x25 rectangles, front and back
2 30x10 rectangles, left and right
and 2 25x30 rectangles, top and bottom
so the area will be (2*10*25) + (2*30*10) + (2*25*30), which gives us 2600 square feet though, not yards.
let's add the doors, windows and others which is 1275, so 2600 + 1275, that gives us 3875 square feet.
now, the paint is 9.5 for square yard, no feet, so let's do some conversion then,
[tex]\bf \begin{array}{ll} yards&feet\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1yd&3ft\\ (1yd)^2&(3ft)^2\\ yd^2&3^2ft^2\\ &9ft^2 \end{array}[/tex]
so, if there are 9 square feet in one square yard, how many square yards are there in 3875 square feet?
[tex]\bf \begin{array}{ccll} yd^2&ft^2\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1&9\\ x&3875 \end{array}\implies \cfrac{1}{x}=\cfrac{9}{3875}\implies \cfrac{3875}{9}=x[/tex]
that's how many yd² are there in 3875 ft².
now, we know for every yd², is $9.50, so then the cost will be
[tex]\bf 9.5\cdot \cfrac{3875}{9}\implies \cfrac{95}{10}\cdot \cfrac{3875}{9}\implies \cfrac{73625}{18}~~\approx~~ \stackrel{\$}{4090.2778}[/tex]
