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Assuming that an experiment's results are 10.1 10.4 and 10.6, find the mean , the average deviation from the mean the standard deviation from the mean and the relative deviation from the mean

Respuesta :

shinmin

Mean:


10.1 + 10.4 + 10.6 = 31.3


31 / 3 = 10.3

 

Average deviation:


 = | (10.1 – 10.3) | + |(10.4 – 10.3)| + |(10.6 – 10.3) |


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                                        3

 

= .2

 

Standard deviation


= √ 1/ n (Summation of x – mean)^2


= √ 1/3 (0.2)^2


= √ 1/3 * 0.04


= √ 0.01


= 0.1

 

Relative Deviation


= standard dev / mean x 100%


= 0.1 / 10.3 x 100


= 0.0097 x 100


= 0.97%