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The system shown has the unique solution (2, y, z). Solve the system and select the values that complete the solution. y = 0 y = 2 y = 3 z = 0 z = 2 z = 3 3x-2y+3z=0 (1) -3x - 5y - 5z= -21 (2) x=2 (3)

Respuesta :

So we are given a system:
[tex]3x-2y+3z=0\\ -3x - 5y - 5z= -21[/tex]
Substitute x = 2 we get the system:
[tex]-2y+3z=-6\\ - 5y - 5z= -15[/tex]
Multiply the first equation by -5 and the second by 2 we get the system:
[tex]10y-15z=30\\ - 10y - 10z= -30[/tex]
Adding the two equations we get :
[tex]-25z=0\text{ then}z=0.[/tex]
We find the value of y by using any of the other equations like this:
[tex]-2y=-6\\y=3.[/tex]
Final solution:
[tex]z=0,y=3[/tex]

Answer:

y = 3

z = 0

Step-by-step explanation:

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