Answer:
The sound level for a noise is 88.9 dB.
Step-by-step explanation:
Given : Intensity of noise is [tex]7.6\times 10^{-4}Wm^{-2}[/tex].
To find : What is the sound level for a noise?
Solution :
The range of the sound intensity is the threshold of hearing which is
[tex]I_o=1\times 10^{-12}Wm^{-2}[/tex]
Intensity of noise is [tex]I=7.6\times 10^{-4}Wm^{-2}[/tex]
The intensity level in d B of a sound of intensity I is defined as:
[tex]I_s=(10dB)\log_{10}(\frac{I}{I_o})[/tex]
Substitute the values,
[tex]I_s=(10dB)\log_{10}(\frac{7.6\times 10^{-4}}{1\times 10^{-12}})[/tex]
[tex]I_s=(10dB)\log_{10}({7.6\times 10^{8})[/tex]
[tex]I_s=(10dB)(8.89)[/tex]
[tex]I_s=88.9dB[/tex]
Therefore, The sound level for a noise is 88.9 dB.
