nenebro2
contestada

The length of a rectangular garden is 8 feet longer than its width. The garden is surrounded by a sidewalk that is 4 feet wide and has an area of 320 square feet. Find the dimensions of the garden.

Respuesta :

wide: 4
longer: 80 (Give me the brainliest plz)

let l be the length of garden

let w be the width of garden

as per the question

l= w+8

320 = (l+8)*(w+8) - (l*w)

on solving the equations we get,

w =12

l =20

so the dimensions of the garden are 20 feet and 12 feet