Respuesta :
Hello,
Let's assume a,b,c the 3 sides of the triangle.
a=9
b=10
c=24-a-b=5
[tex]p= \dfrac{a+b+c}{2} =12\\ S= \sqrt{p(p-a)(p-b)(p-c)} = \sqrt{12*3*2*7} = \sqrt{504} =22,4499...\approx{22}[/tex]
Let's assume a,b,c the 3 sides of the triangle.
a=9
b=10
c=24-a-b=5
[tex]p= \dfrac{a+b+c}{2} =12\\ S= \sqrt{p(p-a)(p-b)(p-c)} = \sqrt{12*3*2*7} = \sqrt{504} =22,4499...\approx{22}[/tex]