Respuesta :

Van't Hoff equation:
ln ([tex] \frac{K_{2} }{K _{1}} [/tex]) = (-ΔH / R) ([tex] \frac{1}{T2} [/tex] - [tex] \frac{1}{T1} [/tex])
T₁ = 298 K and T₂ 764 K
K₁ = 6.5 x 10³  and K₂ = 0.44
R = 8.314 J / mol . K
ln ([tex] \frac{0.44}{6.5 x 10^{3}} [/tex]) = ( [tex] \frac{-ΔHrx}{8.314} [/tex]) x ([tex] \frac{1}{764} [/tex] - [tex] \frac{1}{298} [/tex]) = -38933.85 J/mol