When randomly choosing two cards from a standard deck of cards without replacement, what is the probability of choosing a face card and then an ace? (Remember: standard deck has 52 cards, with 4 aces and 12 face cards)
A 3/221
B 3/168
C 4/221
D 9/169
because There are 12 face cards so The probability of drawing one on the first draw = 12/52 And the probability of drawing a "9" on the second draw = 4/51 So the probability = (12/52) * (4/51) = 4/221 These are dependent events....let A be the probability of drawing a face card and let B be the probabilitiy of drawing "9'....then... P (A ∩ B) = 0 in other words......there is no face card that is also a "9" So...independent events have the relationship that P(A ∩ B) must equal P(A) * P(B)...but 0 ≠ 4/221 So "C" is the correct answer
