Respuesta :
we have that
points (−1, 0) and (0, −3)
step 1
find the slope m
m=(y2-y1)/(x2-x1)-------> m=(-3-0)/(0+1)--------> m=-3
step 2
find yhe equation of the line with m and the point (0, −3)
y-y1=m*(x-x1)-------> y+3=-3*(x-0)-----> y=-3x-3-----> y+3x=-3
the answer is the option
C) 3x + y = −3
see the attached figure
points (−1, 0) and (0, −3)
step 1
find the slope m
m=(y2-y1)/(x2-x1)-------> m=(-3-0)/(0+1)--------> m=-3
step 2
find yhe equation of the line with m and the point (0, −3)
y-y1=m*(x-x1)-------> y+3=-3*(x-0)-----> y=-3x-3-----> y+3x=-3
the answer is the option
C) 3x + y = −3
see the attached figure

Answer:
3x + y = -3
Step-by-step explanation:
Use the slope formula to get m = -3, then use b = -3 to write y = 3x - 3, or
3x + y = -3.