If one of the legs of a right triangle is 4 in and the hypotenuse is 8 in, find the length of the other leg (use a calculator if necessary). Can you guess the measures of the acute angles? IF CORRECT WILL GET BRAINLEST THX
If you want to find the length of other leg (AB) you can use Pythagoras [tex] \sqrt{8 {}^{2} - 4^{2} } \\ = \sqrt{64 - 16} \\ = \sqrt{48} \\ = 4 \sqrt{3} [/tex] So, the length of other leg is 4√3 cm. The acute angles are <B and <C (look at my drawing) sin <B = 8/4= 1/2 <B = 30° <C = 180°-(30+90) = 60° Hope this help!
