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A vertical spring stretches 4.4 cm when a 16-g object is hung from it. the object is replaced with a block of mass 22 g that oscillates up and down in simple harmonic motion. calculate the period of motion.

Respuesta :

Using K= mg/x
where k is a unction of the construction of the spring and has nothing to do with the mass attached to it;
k = 0.016 × 9.81 / 0.044
   = 3.57 N/M
when  a mass of 22 g is used the system will oscillate with a period T = 2π √(m/k)
= 2 × 3.14 ×√ 0.025/3.57)
= 6.28 × 0.0837
= 0.5255
Therefore, the period will be 0.5255 seconds

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