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scdssn
Alright.

We have to split the figure up. For instance, we can make it so we have 2 squares up top and one rectangle on the bottom.

Let's find the area of the squares.
We know that the width of the left square = 12 m and that the length of the right square = 23 m. 
[tex]A=L*W[/tex]
so we have 12m * 23m = 276 m^2. But there are two squares, so let's add another value (or multiply by 2).
276m + 276m = 552 m.

Now, let's solve for the rectangle. In order to find the height, use the width value from the left square, 12 m, and subtract from 31 m.
31 - 12 m = 19m

We already know the width, so let's use the area formula!
19m * 69m = 1,311m^2

Now, let's add up the values for the final answer
1,311 + 552 = total area of 1,863m^2




lugipugi
Very messy but as you can see you first figure out how long the top is which is 23.

Then you split the larger shape into 3 rectangles and for each one figure out the area by multiplying length and breadth. 23*31 and for the middle rectangle you subtract 12 from 31 to get 19. 19*23 and 23*31 again.

Adding the area up 713+437+713=1863m^2
Ver imagen lugipugi

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