Respuesta :

This problem can be completed in 2 ways. Both are acceptable.

Option 1:

This is an isosceles trapezoid that can be divided into a rectangle and two congruent triangles.

The area of the rectangle is the base times the height.

[tex]9 \times 4=36[/tex]

The area of one of the triangles is half the base times the height.

[tex]\dfrac{1}{2} \times 5 \times 4 = 10[/tex]

The other triangle must have that area too.

[tex]36+10+10=56[/tex]

The area is 56 square centimeters.

Option 2:

We can use the area formula for the trapezoid.

[tex]A=\dfrac{b_1+b_2}{2} \times h[/tex]

Where [tex]b_1[/tex] is the length of the shorter base
and [tex]b_2[/tex] is the length of the longer base
and [tex]h[/tex] is the height.

The length of the shorter base is 9.
The length of the longer base is 9+5+5, or 19.

The height is 4.

[tex]A=\dfrac{9+19}{2} \times 4[/tex]

[tex]=56[/tex]

Same answer. The area is 56 square centimeters.

Both options are two acceptable ways the problem can be tackled.

Otras preguntas