Respuesta :
Hello!
If a problem has infinite solutions you will end with a 0, with one it will end with any number and for no solutions you will get a equations that does not equal each other
Ex: 5 = 9
You can do the bottom first since it looks the easiest.
5x - 3 = 5x - 2
subtract 5x from both sides
0x -3 = -2
Add 3 to both sides
0x = 1
0x [tex] \neq 1[/tex]
So it has no solutions
Next you can do the top one
6y + 2 = 3y + 4
subtract 3y from both sides
3y + 2 = 4
Subtract 2 from both sides
3y = 2
Divide both sides by 3
y = [tex] \frac{2}{3} [/tex]
Since this came to a regular number it has one solution
The only one left has the be the one with infinite solutions by we can check
4x + 4y + 8 = x + y + 2
since the left side is the same as the right just multiplied by 4 it has infinite solutions
So the first one has one solution
The second one has infinite solutions
And the third one has no solutions
Hope this helps!
If a problem has infinite solutions you will end with a 0, with one it will end with any number and for no solutions you will get a equations that does not equal each other
Ex: 5 = 9
You can do the bottom first since it looks the easiest.
5x - 3 = 5x - 2
subtract 5x from both sides
0x -3 = -2
Add 3 to both sides
0x = 1
0x [tex] \neq 1[/tex]
So it has no solutions
Next you can do the top one
6y + 2 = 3y + 4
subtract 3y from both sides
3y + 2 = 4
Subtract 2 from both sides
3y = 2
Divide both sides by 3
y = [tex] \frac{2}{3} [/tex]
Since this came to a regular number it has one solution
The only one left has the be the one with infinite solutions by we can check
4x + 4y + 8 = x + y + 2
since the left side is the same as the right just multiplied by 4 it has infinite solutions
So the first one has one solution
The second one has infinite solutions
And the third one has no solutions
Hope this helps!
6y+2=3y+4 can be re-written as 3y = 2, so that y = 2/3. This equation has a solution, only one, unique solution.
4x + 4y + 8 = x + y + 2 could be re-written as
4(x+y) + 6 = 1(x+y), which could be simplified to 3(x+y) = -6, or x+y= -2
Here we have ONLY ONE equation in TWO unknowns. For any value of x we choose, there will be one corresponding value of y. This is a linear equation, and written in the usual form is y = -x -2.
5x – 3 = 5x - 2 could be simplified by subtr. 5x from both sides: -3 = -2. Obviously this is false, and so the equation 5x – 3 = 5x - 2 has no solution.
4x + 4y + 8 = x + y + 2 could be re-written as
4(x+y) + 6 = 1(x+y), which could be simplified to 3(x+y) = -6, or x+y= -2
Here we have ONLY ONE equation in TWO unknowns. For any value of x we choose, there will be one corresponding value of y. This is a linear equation, and written in the usual form is y = -x -2.
5x – 3 = 5x - 2 could be simplified by subtr. 5x from both sides: -3 = -2. Obviously this is false, and so the equation 5x – 3 = 5x - 2 has no solution.