1. AB AB is adjacent to the 50 deg angle. You also know the hypotenuse, so use CAH. [tex] \cos 50^\circ = \dfrac{AB}{9} [/tex] [tex] AB = 9 \cos 50^\circ = 5.8 [/tex]
2. BC BC is opposite the 50 deg angle. You also know the hypotenuse, so use SOH. [tex] \sin 50^\circ = \dfrac{BC}{9} [/tex] [tex] BC = 9 \sin 50^\circ = 6.9 [/tex]
