the balanced equation for the above reaction is as follows; 2HCl + K₂SO₃ ---> 2KCl + H₂O + SO₂ stoichiometry of HCl to SO₂ is 2:1 number of moles of HCl reacted - 15.0 g / 36.5 g/mol = 0.411 mol according to molar ratio number of SO₂ moles formed - 0.411 mol /2 = 0.206 mol since we know the number of moles we can find volume using ideal gas law equation PV = nRT where P - pressure - 1.35 atm x 101 325 Pa/atm = 136 789 Pa V - volume n - number of moles - 0.206 mol R - universal gas constant - 8.314 Jmol⁻¹K⁻¹ T - temperature - 325 K substituting values in the equation
136 789 Pa x V = 0.206 mol x 8.314 Jmol⁻¹K⁻¹ x 325 K V = 4.07 L volume of SO₂ formed is 4.07 L
