rebecca101 rebecca101

14-02-2018
Mathematics

contestada

Two cars leave towns 600 kilometers apart at the same time and travel toward each other. One car's rate is 16 kilometers per hour less than the other's. If they meet in 3 hours, what is the rate of the slower car?

Do not do any rounding.

PLEASE HELP THANK YOU!

Respuesta :

Аноним Аноним

14-02-2018

the difference in speed = 16km/h
1h = 16km
3h = 16 x 3 = 48km

The difference in distance after 3 hours = 48km

600 - 48 = 552
552 ÷ 2 = 276

The slower car covered 276km

Speed of the slower car = distance ÷ time = 276 ÷ 3 = 92km/h

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